Differentiate

sin (3x + 5)

Let y = \sin (3 x + 5) Differentiating y with respect to x we get, \frac{d y}{d x} = \frac{d}{d x} \sin (3 x + 5) = \cos (3 x + 5) \frac{d}{d x} (3 x + 5) [using chain rule] = \cos (3 x + 5) \times 3 = 3 \cos (3 x + 5) So, \frac{d}{d x} \{\sin (3 x + 5)\} = 3 \cos (3 x + 5)