Distinguish by a chemical test:(please do for both)

Dear Student
d)
(NH₄)₂SO₄ on reaction with NaOH releases NH₃ (ammonia) which can be smelled. Na₂SO₄ will not react with NaOH.The reaction is as follows:
2NaOH(aq) + (NH₄)₂SO₄(aq) ==> Na₂SO₄(aq) + 2H₂O(l) + 2NH₃(g).
e)

With barium chloride solution sulphuric acid will give white precipitate,

$BaC{l}_2 (aq.)+ H_{2}S{O}_4 (aq.) \to BaS{O}_{4 }\left(s\right) + 2HCl (aq.)$

when barium chloride is reacted with HNO₃ all the reactant and the products will be in aqueous state,
$BaC{l}_{2 }(aq.) + 2HN{O}_3(aq.) \to Ba{\left(N{O}_3\right)}_2 (aq.) + 2HCl (aq.)$

and, when barium chloride is added to HCl solution no reaction will occur,
$BaC{l}_{2 }(aq.)+ HCl (aq.) \to no reaction$
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