Draw lines l and m intersected by a transversal t. Construct angle bisectors of the cointerior angles on one side of the transversal. Now measure the angle formed by the bisecting rays.

As my exam is on 20th Thursday, please answer my question urgently.

Thanks

Answer :

We follow these steps to construct our diagram , As :

Step 1 : Draw a line l  .

Step 2 :  Draw a line AB that  intersect our line l at " A " . and take any point  "  P " on line AB .

Step 3 :  Take any  radius and center "  A "  draw an arc that intersect our line l at  " C "  and line AB at "  D "

Step 4 : With same radius and center "  P "  draw  semicircle  that intersect  line AB at "  E " and " G  " .

Step 5 :  Now take radius as length of CD and center " E "  draw an arc that intersect our previous arc at "  F " .

Step 6 :  Now Join PF and extend it that line is our required line " m "

Step 7 : Now take radius as PG and take center " F " and " G " and draw arcs these arcs intersect at " H " .

Step 8 : Now take radius as AD and take center " C " and " D " and draw arcs these arcs intersect at " I " .

Join angle bisecting rays PH and AI these rays intersect at  "  X " .

Now we measure  AXP  = 90°


 

  • 6
let the parrellel line be l:AB

M:CD and they intersect ab and CD at p

and q respectively

po and qo are bisectors of int angle bpq

and dqp resp.

angle bpq+dpq ::: 180

1/2bpq+1/2dpq:::90

opq+oqp:::90

in triangle opq by angle sum property

angle poq ::: 90
the bisectors form the angle of 90° please hands up
  • 4
What are you looking for?