draw the figure in which triangles ABC and ADC are equilateral triangles on common base AC each side of triangle beng 2a units.
vertices A and C lie on the x- axis and vertices B and D lie on y- axis. O is the midpoint of AC and BD. find the coordinate point of B
please please please answer this query within 3 hrs. tomorrow is my maths test
Answer :
Given
ABC and ADC are equilateral triangles with same base AC ,
And length of each side = 2a unit
SO,
AB = BC = AC = AD = DC = 2a unit
And As given O is the middle point of AC and BD , SO,
OA = OC = a unit
In triangle AOB we apply Pythagoras theorem and get
AB2 = OA2 + OB2
OB2 = ( 2a )2 - a2 ( As we know AC = 2a and OA = a unit )
OB2 = 4a2 - a2
OB2 = 3a2
OB = a unit
SO coordinate at B = ( 0 , a ) ( Ans )
Given
ABC and ADC are equilateral triangles with same base AC ,
And length of each side = 2a unit
SO,
AB = BC = AC = AD = DC = 2a unit
And As given O is the middle point of AC and BD , SO,
OA = OC = a unit
In triangle AOB we apply Pythagoras theorem and get
AB2 = OA2 + OB2
OB2 = ( 2a )2 - a2 ( As we know AC = 2a and OA = a unit )
OB2 = 4a2 - a2
OB2 = 3a2
OB = a unit
SO coordinate at B = ( 0 , a ) ( Ans )