draw the graphs of 3x+2y=0 and 2x+3y=0. What is the oint of intesection of the two lines representing the above equations?



the given line 3x+2y=0 ...(1) passes through the point (0,0).
as x=0 and y=0 satisfies the eq(1).
and x =2 and y = -3 also satisfies the eq(1) as 3*2+2*(-3)
= 6-6
= 0
thus by joining the points (0,0) and (2, -3) we can draw the line 3x+2y=0
the line 2x+3y=0 ........(2) passes through the origin as 2*0+3*0 =0
x = 3 and y = -2 also satisfies the eq(2) .2*3+3*(-2) = 6-6
=0
therefore point (3, -2) also lies on the line (2)
hence by joining the points (0,0) and ( 3, -2) , we can draw the line 2x+3y =0


the given line passes through the origin.
their intersection point is origin.

hope this helps you

 

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