Eliminate theta...x=a cos theta, y=b sin theta
x=a cos theta, y=b sin theta.
we know the identities of trigonometry in terms of sin theta and cos theta
sin2K+cos2 K=1, hence we should try to convert the above into sin2K+cos2 K=1, so as to eliminate the sin theta and cos theta
I think,
x2b2+y2a2 is the correct answer because,
let theta be Z
x2=a2cos2Z
y2=b2sin2Z
x2b2+y2a2=a2b 2cos2Z+a2 b2sin2Z
by taking a2b 2 common the identity is used to remove the theta.
we know the identities of trigonometry in terms of sin theta and cos theta
sin2K+cos2 K=1, hence we should try to convert the above into sin2K+cos2 K=1, so as to eliminate the sin theta and cos theta
I think,
x2b2+y2a2 is the correct answer because,
let theta be Z
x2=a2cos2Z
y2=b2sin2Z
x2b2+y2a2=a2b 2cos2Z+a2 b2sin2Z
by taking a2b 2 common the identity is used to remove the theta.
