evaluate i37+1/i67 Share with your friends Share 6 Atul Bisht answered this i37+1/i67=i4*9+1+i-67=1+i+i4*-17+i1+i-1+1=i+i=2i -6 View Full Answer Kalyni answered this i didnt understand please make it clear 2 Raman Mishra answered this =i37 + 1/i67=i36+1 + 1/i64+3=(i4)9 . i + 1/ (i4)16+ i3=1.i + 1/ 1-i (as i2 = -1)=i+1/-i=(-(i2)+1 )/-i ( take Lcm )=(1+1)/-i=2/-irationalize=(2/-i )*-i/-i=(2i / -(i2)=-2i/1= -2i=(0-2i) -3 Diksha Yadav answered this =i37+ 1/i67=i36+1+ 1/i64+3=(i4)9. i + 1/ (i4)16+ i3=1.i + 1/ 1-i (as i2= -1)=i+1/-i=(-(i2)+1 )/-i ( take Lcm )=(1+1)/-i=2/-irationalize=(2/-i )*-i/-i=(2i / -(i2)=-2i/1=-2i=(0-2i) -10 Klyen Dave answered this i37+1/i67 =(i2)18.i + 1/(i2)33.i =1.i + 1/-1.i (Since i2=-1) =i -1/i =(i2 - 1)/i =(-1-1)/i =-2/i Now, multiplying by i/i, -2/i . i\i =-2i/i2 =-2i/-1 =2i 11 Hari answered this That 9th sum...prove that and tell me the answer -4
