Experts answer urgently Share with your friends Share 0 Kavita Verma answered this Dear Student, 2x + y + 25 = 3x - y + 13 = 3x + 2y + 16Let's take 2x + y + 25 = 3x - y + 13⇒ 32x + y + 2 = 53x - y + 1⇒ 6x + 3y + 6 = 15x - 5y + 5⇒ 9x - 8y - 1 = 0 ............... eq 1Now let's take 3x - y + 13 = 3x + 2y + 16⇒ 3x - y + 1 = 3x + 2y + 12⇒ 2 3x - y + 1 = 3x + 2y + 1⇒ 6x - 2y + 2 = 3x + 2y + 1⇒ 3x - 4y + 1 = 0..................eq 2eq 1 - 3 × eq 2, we get :-9x - 8y - 1 - 33x - 4y + 1 = 09x - 8y - 1 - 9x + 12y - 3 = 04y - 4 = 0y = 1Now substitute this value in eq 1, we get :-9x - 8y - 1 = 09x - 8 -1 = 0x = 1 Therefore, option (3) x = 1, y = 1 is correct. Regards, 0 View Full Answer