EXPERTS, I HAVE THESE PROBLEMS TO SOVE:
Q1) How many Linear Equation in x and y can be satisfied by x = 3, y = 4?

Q2) Give the geometrical representation of the equation 3x + 15 = 0 as an equation :

a) In 1 Variable.

b) In 2 Variables.

Q3) If PQRS is a paralleloogram, then what would be the value of angle Q - angle S?

Q4) Prove that diagonal of a parallelogram divides it into 2 congruent triangles.

Q5) Two parallel lines l and m are intersected by a transversal t. Show that quadrilateral formed by angles is a rectangle.

Q6) Prove that the quadrilateral formed by internal angle bisectors of any quadrilateral is cyclic.

Q7) In quadrilateral PQRS, if angle P = 60oand angle Q : angle R : angle S = 2 : 3 : 7, then find the value of angle S.

Q8) Show that the median divides a triangle into 2 triangles of equal areas.

Q9) ABCD is a quadrilateral whose diagonal AC divides it into 2 parts equal in area, then find ABCD.

Q10) If area of parallelogram ABCD= 25cm2 and on the same base CD, triangle ABCD is given such that ar (triangle BCD) = x, then find the value of x.

EXPERTS PLEASE HELP ME AND PLEASE REPLY AS FAST AS YOU CAN !!!!!!!!!!!!!

first answer is infinite equations
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Q10) ar(triangle BCD) = 1/2 ar(llgm ABCD) [as triangle is on the same base and between same parallels]
ar(triangle BCD) = 1/2 X 25cm2
ar(triangle BCD) = 12.5cm2
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Q3) angle Q - angle S = 0 (opposite angles of a parallelogram are equal)
Q4) In triangles ABD and BCD
AB = DC (opposite sides of a llgm are equal)
Angle BAD = Angle BCD (opposite angles of a llgm are equal)
BD = BD (common)
Hence, proved

Q7) angle P + angle Q + Angle R + Angle S = 360
60 + 2x + 3x + 7x = 360
5x + 7x = 360 - 60
12x = 300
x = 300/12
x = 25
angle S = 7x
= 7 X 25
= 175

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