Experts, Meritnation, Please Solve the following: In triangle ABC, CM bisects AB equally at M and BQ bisects to CM equally at P. If Q is on AC, then prove that AQ = 2QC. {Please don't provide certified answer... I want only experts answer to any without providing any web link or certified answer} Share with your friends Share 0 Brijendra Pal answered this Hi, Hi, Construct a line MT parallel to BQNow in triangle AMT and ABQMT∥BQ and angle A is common so because of these two parallel lines angle AMT will be equal to ABQ, corresponding angle and since two angle is same so third will automatically be same so △AMT~ABQ AA similarityso AMMB=ATTQor AT = AQ since AM = MB .......1now again using same similarity concept in triangle CQP and CTM since PQ∥MT and angle PCQ is common so by the same process as done earlier△CQP~CTM AA similarityso CQQT=CPPMor CQ = QT since PC=PM .......2now using equation 1 and 2 AT = QT = QC SO AQ = AT+TQ = QC+QC= 2QC 1 View Full Answer Akshaya answered this Actually the amswer for this is in the best app called photomath .Ok -5 Gargi answered this not of your grade 7 -3
