Experts please answer this question Share with your friends Share 0 Vipra Mishra answered this Dear Student Let x1 represent the person’s distance from the nearer cliff (right hand side) and x2 his distance from the farther cliff (left hand side). The sound for the first echo travels distance 2 x1 . For the second echo distance travelled is, 2 x2 . For the third echo, distance =2 x1+2 x2Then as given, The second echo arrives 1.92 s after the firstsecond echo distance travelled - first echo travels distancespeed of sound = 1.922 x2-2 x1340= 1.92 x2- x1 =326.4Similalrlythird echo distance travelled - second echo travels distancespeed of sound = 1.472 x1+2 x2-2 x2340= 1.47x1=249.9 m x2 =326.4+249.9 =576.3 mSo d = x1+x2 =826.2 m Regards 1 View Full Answer
