Experts please help The point ([p + 1], [p]) is lying inside the circle x2 + y2 - Maths -

Question

Experts please help

The point ([p + 1], [p]) is lying inside the circle x2 +
y2 – 2x – 15 = 0 Then the set of all values
of p is (where [·] represents the greatest integer
function)
(1) [–2, 3)
(2) (–2, 3)
(3) [–2, 0) â‹ƒ (0, 3)
(4) [0, 3)

Kuldeep Verma · Accepted Answer

Dear student<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_5ce15c6984dd9%20jpg">hope
you get it regards

Experts please help

The point ([p + 1], [p]) is lying inside the circle x² + y² – 2x – 15 = 0. Then the set of all values of p is (where [·] represents the greatest integer function).
(1) [–2, 3)
(2) (–2, 3)
(3) [–2, 0) ⋃ (0, 3)
(4) [0, 3)

Dear studenthope you get it regards

Experts please help The point ([p + 1], [p]) is lying inside the circle x2 + y2 – 2x – 15 = 0. Then the set of all values of p is (where [·] represents the greatest integer function). (1) [–2, 3) (2) (–2, 3) (3) [–2, 0) ⋃ (0, 3) (4) [0, 3)

Dear studenthope you get it regards

Experts please help

The point ([p + 1], [p]) is lying inside the circle x² + y² – 2x – 15 = 0. Then the set of all values of p is (where [·] represents the greatest integer function).
(1) [–2, 3)
(2) (–2, 3)
(3) [–2, 0) ⋃ (0, 3)
(4) [0, 3)