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D e a r s t u d e n t, A s s u m i n g t h e q u e s t i o n t o b e : \sqrt{2} s e c θ + \tan θ = 1 \sqrt{2} + \sin θ = \cos θ \cos θ - \sin θ = \sqrt{2} \frac{\cos θ}{\sqrt{2}} - \frac{\sin θ}{\sqrt{2}} = \frac{\sqrt{2}}{\sqrt{2}} \sin (45^{\circ} - θ) = 1 = \sin (90^{\circ}) 45^{\circ} - θ = 90^{\circ} θ = - 45^{\circ} R e g a r d s

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