Expertss plsssvplss help me
Dear Student,
Capacitance is inversely proportional to the distance between the plates, so when the distance is reduced by half then
(i) the capacitance will increase by two times of its initial.
(ii) The charged stored will remain unchanged as the capacitor is disconnected from the battery.
(iii) potential difference which is given by V = Q/C reduces to half od its initial value as the capacitance doubles itself and charge remains constant.
(iv) Electric field between the plates remain unchanged as the charge distribution is fixed.
(v) energy stored () in the capacitor is decreased to half as the capacitance is doubled.
Regards
Capacitance is inversely proportional to the distance between the plates, so when the distance is reduced by half then
(i) the capacitance will increase by two times of its initial.
(ii) The charged stored will remain unchanged as the capacitor is disconnected from the battery.
(iii) potential difference which is given by V = Q/C reduces to half od its initial value as the capacitance doubles itself and charge remains constant.
(iv) Electric field between the plates remain unchanged as the charge distribution is fixed.
(v) energy stored () in the capacitor is decreased to half as the capacitance is doubled.
Regards