Factorise : (a2-2a)2-23(a2-2a)+120

(a2 – 2a)2 – 23(a2 – 2a) + 120

Let (a2 – 2a) = x, then given polynomial becomes

x2 – 23x + 120

= x2 – 15x – 8x + 120

= x(x – 15) – 8 (x – 15)

= (x – 15) (x – 8)

On substituting the value of x, we get

(a2 – 2a)2 – 23(a2 – 2a) + 120 

= (a2 – 2a – 15) (a2 – 2a – 8)  

= (a2 – 5a + 3a – 15) (a2 – 4a + 2a – 8)  

= (a – 5) (a + 3) (a – 4) (a + 2) 

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