factorize                                           b2c3+8bc4+12c5

Q 21
We have,

b2c3 + 8bc4 + 12c5

= c3 (b2 + 8bc + 12c2)

= c3 (b2 + 6bc + 2bc + 12c2)

= c3 [b(b + 6c) + 2c(b + 6c)]

= c3 (b + 6c)(b + 2c)

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