find a for which the coefficient of middle terms in the expansion of (1+ax)4 and (1-ax)6 are equal Share with your friends Share 2 Lovina Kansal answered this Dear student In the expansion of 1+ax4Middle term=4C2ax2=6a2x2In the expansion of 1-ax6,Middle term=6C3-ax3=-20a3x3It is given that:Coefficient of the middle term in (1+ax)4=Coefficient of the middle term in (1-ax)66a2=-20a3⇒a=0, a=-310 Regards 1 View Full Answer