Find areas of polygons

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Construction : Join EF and DF such that EF = DF = 1 cm Now, AB = 3 cm, CF = DF + DC = 1 + 2 = 3 cm and BC = 6 cm and AF = AE + EF = 5 + 1 = 6 cm NOw area of AFBC = BC \times AB = 6 \times 3 = 18 {cm}^{2} area of DEF = \frac{1}{2} \times EF \times DF = \frac{1}{2} \times 1 \times 1 = \frac{1}{2} {cm}^{2} SO, Required area = area of AFBC - area of DEF = (18 - \frac{1}{2}) {cm}^{2} = (18 - 0.5) {cm}^{2} = 17.5 {cm}^{2}

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