Find d2y/dx2 if y=3at/1+t and x=2at2/1+t Share with your friends Share 8 Vipin Verma answered this y = 3at1+t , x =2at21+tSo dydt=3a (1+t) - 3at (1)(1+t)2=3a +3at -3at(1+t)2 =3a(1+t)2 (1)And dxdt =4at(1+t)-2at2(1)(1+t)2 =4at+4at2-2at2(1+t)2=4at+2at2(1+t)2 (2)So divide (1) by (2), we havedydtdxdt=3a(1+t)24at+2at2(1+t)2 dydx =3a4at+2at2Hence d2ydx2 =ddt(dydx)×dtdx = ddt(3a4at+2at2)×(1+t)24at+2at2=0×(4at+2at2) -3a (4a +4at)(4at+2at2)2×(1+t)24at+2at2=-3a (4a +4at)×(1+t)2(4at+2at2)3 (ans) 19 View Full Answer
