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find dy/dx if y = log sinx.

$y = \log (\sin x) \frac{d y}{d x} = \frac{1}{(\sin x)} \cdot \frac{d}{d x} (\sin x) \Rightarrow \frac{d y}{d x} = \frac{\cos x}{\sin x} \Rightarrow \frac{d y}{d x} = \cot x$

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