Find dy/dx , when y = (sin x + x2) / (cot 2x) . Share with your friends Share 12 Varun.Rawat answered this We have, y = x2 + sin xcot 2x = x2 + sin x tan 2xdifferentiating both sides with respect to x, we get dydx = x2 + sin x ddxtan 2x + tan 2x ddxx2 + sin x⇒dydx = x2 + sin x 2 sec22x + tan 2x 2x + cos x⇒dydx = 2x2sec22x + 2 sin x sec22x + 2x tan 2x + cos x tan 2x 40 View Full Answer