find inverse of [3 1 2 4]if it exits Share with your friends Share 0 Manbar Singh answered this Let A = 3124Now , A = 3124 = 12-2 = 10Since A ≠0 , So A-1 exists.Let Aij be the cofactors of aij in A.Now , A11 = -12 ×4 = 4 A12 = -13 ×2 = -2 A21 = -13 ×1 = -1 A22 = -14 ×3 = 3Now , AdjA = 4-1-23Now , A-1 = AdjAA = 110 4-1-23 1 View Full Answer