Find Molarity and Molality of B of A solution of A (MM=20) and B (MM=10), [Mole fraction XB=0.6][Mole fraction XB=0.6] having density 0.7 gm/ ml.

The relation between molarity and mole fraction isXB =MMAM(MA~MB)+dWhere XB = mole fraction of BM= molarityMA = Molecular mass of AMB = Molecular mass of Bd= densityXB =MMAM(MA~MB)+d0.6=M ×20M(20 ~10) + 0.7Solve for MMolarity= 0.03 MolarThe relation between molality and mole fraction isXB =mMA1+mMAWhere XB = mole fraction of Bm= molalityMA = Molecular mass of AXB =mMA1+mMA0.6 =m×201+m×20Solve for mMolality =0.075 m 

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using these formulas u can calculate the required things
molality = ((X solute) / (X solvent)) * ((100) / (molarity*molecular mass of solvent))
molality = (1000* molarity) / (1000* density - molarity*Imolecular mass of solute)
molarity = (10(%W / V)) / (molecular mass of solute)
% W / V = (% W / W) * density of solution
 
pls read the formulas correctely and also note them properly
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