find ques 10 plz its very urgent Share with your friends Share 0 Shruti Tyagi answered this Dear Student, i) sum of interior angles of polygon=n-2×180for a pentagon n=5hence sum of interior angles of pentagon⇒5-2×180⇒3×180⇒540°ii) Since AB∥DEthen AE is transverse line intersecting two parallel linestherefore ∠A+∠E=180 --adjacent supplementary anglesiii) Let ∠B=5x,∠C=6x and ∠D=7x∴∠A+∠B+∠C+∠D+∠E=540⇒5x+6x+7x+180=540⇒18x=540-180⇒18x=360⇒x=20Hence ∠B=5×20⇒100,∠C=6×20⇒120 and ∠D=7×20⇒140 Regards, 1 View Full Answer M.n.brindha answered this Your answer NCERT in math your name. 1
