Find the 10th and nth terms of the GP 12,4, 4/3,4/9.........

first term (a) = 12

common ratio (r) = 1/3

T ₁₀  = ar ^n-1

= 12 (1/3)^10-1

= 12 (1/3) ⁹

= 12 ( 1/19683)

=4/6561

ANS 4/6561

T_n = ar ^n-1

= 12(1/3)^n-1                            ans