Find the angular elevation of the Sun when the shadow of a 10m long pole is 10√3m.

let the length of the pole be AC = 10 m

length of its shadow be BC =

let the angle of elevation of the sun be θ. 

then in the right angled triangle ACB,

thus the angular elevation of Sun is 30 deg

  • 8

 the answer is30 degrees

  • 3

 k....thnx...but how???

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