Find the area between the curves y=|x-1| and
y= -|x-1|+1
Answer :
Firs we form a table for different value of x and y for both equation , As :
Now we represent these points on x - y , plane , As :
Here Length of AC = 1 unit and Distance ( Height ) between vertices D and line AC = 0.5 unit and between vertices B and line AC = 0.5 unit
We know Area of triangle =
So,
Area of triangle ABC = Area of triangle ADC ,
And
Area of triangle ABC =
And
Area of triangle ADC = 0.25 unit2
So,
Area of required ABCD = 0.25 + 0.25 = 0.50 unit2 ( Ans )
Firs we form a table for different value of x and y for both equation , As :
y = | x - 1 | | y = - | x - 1 | + 1 | ||
x | y | x | y |
0 | 1 | 0 | 0 |
0.5 | 0.5 | 0.5 | 0.5 |
1 | 0 | 1 | 1 |
1.5 | 0.5 | 1.5 | 0.5 |
2 | 1 | 2 | 0 |
-0.5 | 1.5 | -0.5 | -0.5 |
Now we represent these points on x - y , plane , As :
Here Length of AC = 1 unit and Distance ( Height ) between vertices D and line AC = 0.5 unit and between vertices B and line AC = 0.5 unit
We know Area of triangle =
So,
Area of triangle ABC = Area of triangle ADC ,
And
Area of triangle ABC =
And
Area of triangle ADC = 0.25 unit2
So,
Area of required ABCD = 0.25 + 0.25 = 0.50 unit2 ( Ans )