Find the area of a quadrant of a circle whose circumference is 22 cm. Take PIE= 22/7 Share with your friends Share 0 Vivek answered this hope it helps.. 2 View Full Answer Divya Janjua answered this circumference of circle = 22 cmtherefore 2 pi r = 22r = 22 x 7 / 2 x 22on cancellationr = 7 / 2 = 3.5 cmtherfore area of quadrant = pi r square / 4 = 22 / 7 x 3.5 x 3.5 x 1 / 4 = 38.5 / 4 cm square = 9.625 cm square 1 Namrata Chhabra answered this Circumference of a quadrant is 1/4 the circumference so the circumference of the circle is 4x22=88cm, Also circumference of a circle is 2(pi)R.=>2x22/7xR=88cm >R=88x7/22x2 >R=88x7/44 >R=2x7 >R=14cm 0 Mohammed Meeran answered this 2πr =22R= 22 *7/22 *1/2 So r= 7/2 Now area of quadrant = πr²ϴ/360 22/7*49/4*90/360 So area of quadrant=9.6250 0 Harbir Singh answered this circumference = 2*pi*r22 = 2 * 22/7 * rr = 22 * 7/22 * 1/2r = 7/2 cmarea of quadrant = 1/4 * pi * r * r= 1/4 * 22/7 * 7/2 * 7/2= 77/8 cm sq. -1 Rittul Arya answered this circumference of circle= 2 XpieXr22= 2X(22/7)Xr(22X7)/(22X2)=r7/2=rarea of quadrant= 1/4X pie X r^2=(1/4)X(22/7)X(7/2)^2=77/8 0 Sweety Purnima Lugun answered this as u knw circumference of a circle = 2 * pie * radius, 22 = 2 * 22/7 * r , r = 7/2area of circle = 1/4 * pie * radius * radius = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 ans -1