Find the area of the given trapezium..
Help me :(
Q.(iii)

Draw CO parallel to AD
So the area of trapezium ABCD = area of //gm AOCD + area of triangle OBC
=> AO = CD (//gm) = 20 cm
=> OB = 32 cm - 20 cm = 12 cm
area of triangle = square root of (s(s-a)(s-b)(s-c))
= square root of (19 * 7 * 3 * 9)
= 3 * square root of (399) = 3 * 19.97 = 59.91 cm²
3 * square root of 399 = 1/2 * b * h = 1/2 * 12 * h = 6h
h = 1/2 * square root of 399 = 1/2 * 19.97 = 9.985
//gm area = 20 * 9.985 = 199.7 cm²
trapezium area = 59.91 cm² + 199.7 cm² = 259.61 cm²