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Find the area of the triangle whose vertices are (1,-4), (3,-2) and (-3,16)

@nrenu: You had provided the correct answer. Keep Posting.

Here, the formula used is:

Area of triangle = 

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24 units square..

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Ar of triangle = 1/2 [1(-2-16)+3(16+4)-3(-4+2)]

                         =1/2 [1(-18)+3(20)-3(-2)]

                         =1/2[-18+60+6]

                          =1/2(48) = 24 sq units

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