Find the centre and radius of the circle x^2+y^2-ax-by=0 Share with your friends Share 0 Manasa Pallaki answered this Dear Student, x2+y2-ax-by=0Comparing the given equation with x2+y2+2gx+2fy+c=02g = -a and 2f = -b and c = 0So, g=-a2 and f=-b2But center=-g,-f=a2,b2Radius=g2+f2-c=a22+b22=a24+b24=a2+b22 Regards -1 View Full Answer Fahim Basheer answered this center coordinate = (a/2 , b/2) radius = (a2+b2)1/2 . 2-1 2
