Find the coordinates of the point(s) on the line x+y+3=0, whose distance from the line x+2y+2 = 0 is 50.5.
Let the coordinates of the required point be (x1, y1).
It is given that this point lies on x + y + 3 = 0
Therefore, x1 + y1 + 3 = 0 .... (1)
Now, length of the perpendicular from (x1, y1) to x + 2y + 2 = 0 is √5.
On solving equation (1) and (2), we get
x1 = -9, y1 = 6 and x1 = 1, y1 = -4
So, the coordinates of the required point are (-9, 6) and (1, -4).