Find the equation of the chord of the circle x2+y2-4x=0 which is bisected at the point (1,1).
{Please mention the requires formula in details)

Here is the answer to your question From the equation of circle, centre is (2,0) and from equation of radius root g^2+f^2-c =0 radius is 2 units. Now the line drawn from centre to chord is perpendicular to chord. Slope ofOD is -1 so slope of AB chord is 1. Now we know a point on chord and slope of chord and can write equation of chord whic is Y-1/x-1=1 y-x =0

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x - y = 0
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X-Y=0
SORRY I DOES NOT KNOW SOLUTION BUT SURELY THIS ANSWER IS CORREST

 
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Here is the right answer

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The equation of the chord of the circle x2 + y2 = 81 which is bisected at the point (_2, 3) is
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A shortcut to solve it is to use T=S1 form this will give it easy and exact answer

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