find the equation of the circle passing through origin and cutting off intercepts a and b from x axis and y axis

Since, the circle cuts intercepts of a and b on the x – axis and y – axis respectively, therefore, the line joining the points (a, 0) and (0, b) will be the diameter of the circle.

Let the co-ordinates of the centre of the circle be h and k respectively.

Therefore, h = (a + 0)/2 and k = (b + 0)/2 

Let the radius of the circle be r

Therefore, r2 = (0.5aa)2

 + (0.5b – 0)2

Equation of the circle is as follows:

(xh)2 + (yk)2 = r2

Equation: x2 + y2axby = 0

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