find the equation of the circle through the intersection of the circles x2+y2-8x-2y+7=0 and x2+y2-4x+10y+8=0 and passing through the point (-1,-2) Share with your friends Share 1 Brijendra Pal answered this Hi, The required circle would be x2+y2-8x-2y+7+λx2+y2-4x+10y+8= 0 Now since it passes through -1,-2put x = -1 and y = -2 and find λ and put back the value of λ to find the requied circle. Regards -3 View Full Answer Sahithya answered this jh -1