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Find the equation of the ellipse whose foci are at (0,+-6) and the length of whose minor axis is 16.

c=+-6   2 * b = 16 (length of minor axis)          c2=a2-b2
                   b = 8                                            62=a2-82
                                                                       a2 = 36 +64
                                                                       a2 = 100
                                                                       a = +-10

equation of ellipse = y2/100 + x2/64 = 1

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eqn. of the ellipse is of the form  x2   +   y2    =1
                                                     b2         a2
given,
b=semi minor axis=16/2=8
now,c2=a2-b2
or     62=a2-82
or     a2=36+64=100
or     a=10
Eqn. of the ellipse is   x2   +  y2    =1
                                   64      100
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