find the equation of the line passing through the point (0,3) and perpendicular to the line x-2y+5=0 Share with your friends Share 0 Neha Sethi answered this Dear student The eq of the line perpendicular to the line x-2y+5=0is 2x+y+c=0 where c is a constantThe line passes through the point 0,3So it will satisfy the eq 2x+y+c=0⇒20+3=-c⇒c=-3So eq becomes 2x+y-3=0 Regards 0 View Full Answer Mishika answered this Please find this answer 1
