Find the equation of the lines through the point of intersection of 2x + 3y =7 and x + 3y =5, which cuts the co-ordinate axes at points equidistant from origin. Share with your friends Share 0 Saksham Tolani answered this Dear Student, Since, required line cuts the co-ordinate axes at points equidistant from origin.So, let required line be,xa+ya=1x+y=a ----(1)Now, solving, the other two lines, i.e. 2x+3y=7 ---(2)x+3y=5 ---(3)(2)-(3)x=2y=1So, these values will satisfy equation (1),So,2+1=aa=3So, required line is,x+y=3 Regards! 2 View Full Answer