find the general solution of cosecx=1+cotx Share with your friends Share 8 Shipra D. answered this cosecx=1+cotx⇒1sinx=1+cosxsinx⇒1sinx-cosxsinx=1⇒1-cosx=sinx⇒1-1-sin2x=sinx⇒1-sinx=1-sin2xSquaring both sides⇒1+sin2x-2sinx=1-sin2x⇒2sin2x-2sinx=0⇒sin2x-sinx=0⇒sinxsinx-1=0⇒sinx=0, 1⇒x=0, x=nπ, where n∈ℤ, sinx=1 ⇒sinx=sinπ2⇒x=nπ+-1nπ2, where n∈ℤ 16 View Full Answer
