find the general solution of cot2x + 3cosec x + 3=0

Hi Ameen , 
We know Cot2​x = Cosec2​x - 1 
Substitute this , 
We get the equation like , 
Cosec2​x - 3 Cosec x + 2 =0 
Therefore , solve this quadratic equation , we get , 
Cosex x = 1,2 

Therefore , x= (4n+1)Pi/2 or x=(3n+1)Pi/6 , 
where n is a integral number .. 
Thanks , 
Daryl
  • -18
Cot2x + 3Cosec(x) +3 = 0
Since, Cot2x = Cosec2x - 1
=> Cosec2x - 1 + 3Cosec(x) + 3 = 0
=> ​Cosec2x + 3Cosec(x) + 2 = 0
Let Cosec(x) = y,
y2 + 3y + 2 = 0
y+1 = 0       (or)        y+2 = 0 
Therefore,
sinX= -1 or sinX=-1/2
=> x= nπ + (-1)n7π/6    or    x= nπ + (-1)n3π/2


Peace :))
  • 27
peace broos
  • -14
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