find the general solution of the equation 4 cos^2x+root 3=2(root 3+1)cosx​

4 cos2x + √3 =2 cosx(√3+1)
4 cos2x-2 cosx(√3+1) + √3 = 0
4 cos2x-2√3 cosx-2 cosx+√3 = 0
2 cosx(2 cosx(2 cosx-3)-1(2 cosx-√3)=0
(2 cosx-1)(2 cosx-√3)=0
Cosx=1/2    , √3/2
Cosx=√3/2=cos ∏/3      , Cosx=1/2=cos ∏/6
 
Therefore,  x=2n∏+∏/3     or x=2n∏+∏/6
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General solution of trigonometric equations
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