find the general solution of the equation:  cos3x=sin2x?

Cos3x= sin2x

Or, sin(90-3x)= sin2x

Or, 90-3x=2x

Or, x= 18

  • -18

cos3x=sin2x

sin(90-3x)=sin2x

5x=90 or x=18 then take angle is 18 and do general solution

  • -16
TO FIND - GENERAL SOLUTION cos3x =sin 2x
cos3x = sin 2x
​cos (π/2- 3x)= sin 2x                 (as cos (π​/2- x)= sin x)
so ,           π/2-3x= 2x
​               π/2 = 5x
           π/10= x
so the general soltuion be ,
x=(4n+1)π/10     or   x=(4n-1)π/10       ,  where n belongs x


                                              HENCE SOLVED
 
  • -9
cos 3x = cos (π/2 - 2x)
3x = 2nπ ± (π/2 - 2x)
x= 2nπ/5 + π /10  or   2nπ - π/2, n∈z
  • 22
  • x=II/10+2nII/5
  • -2
What are you looking for?