Find the greatest number of four digits which is exactly divisible by each of 12, 18, 40 and 45.

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Suresh Anand answered this

Find LCM of 12, 18, 40 and 45: which comes out to be 360.

Now, 360 x 30 = 10800

360 x 29 = 10800 - 360 = 10440

360 x 28 = 10080

360 x 27 = 9720

Clearly, 9720 is the largest four digit number divisible by 12, 18, 40 and 45 as 9720 will be a multiple of these numbers as it is a multiple of one of their common multiples.

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Dan answered this

9720 is a multiple of of these all numbers

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Dan answered this

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Krutin Pradeep Bhat answered this

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Suryansh Singh answered this

40= 2×2×2×5= 2³×5

45= 3×3×5= 3²×5

L.C.M of 12 ,18,40,&45= 2³×3²×5

L.C.M of 12 ,18,40,&45= 2×2×2×3×3×5

L.C.M of 12 ,18,40,&45= 360

Now divide the largest 4 digit number 9999 by 360

9999 ÷ 360

9999= 360× 27 +279

Remainder= 279

Then Subtract the remainder from 9999

9999- 279= 9720

Hence, greatest number of four digits which is divisible by 12, 18, 40 & 45
= 9720
Hope this will help you....

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Anushka Raj answered this

HCF 9720

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Harshit Singh answered this

9720 is the greatest number divisible by 12, 18, 40 and 45.

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Soumyadeep Ghosh answered this

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Namit answered this

360

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Ashish Kumar answered this

40= 2?2?2?5= 2??5

45= 3?3?5= 3??5

L.C.M of 12 ,18,40,&45= 2??3??5

L.C.M of 12 ,18,40,&45= 2?2?2?3?3?5

L.C.M of 12 ,18,40,&45= 360

Now divide the largest 4 digit number 9999 by 360

9999 ? 360

9999= 360? 27 +279

Remainder= 279

Then Subtract the remainder from 9999

9999- 279= 9720

Hence, greatest number of four digits which is divisible by 12, 18, 40 & 45
= 9720
Hope this will help you....

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Jahnavi Kumari answered this

LCM of 12 , 18 ,40 , 45=360 Now divide by 9999 / 360 =Q = 27 R = 279 Then multiply by 360 and 27 = 9720

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Sandeep Singh answered this

find the LCM the multiple of of LCM then right but is answer multiple right there multiple of the day Navy then that the greatest 4 digit number when it is not coming and that number is exactly divisible by 12; 18 ;40; 45

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Ashwani Kumar answered this

40= 2?2?2?5= 2??5
45= 3?3?5= 3??5
L.C.M of 12 ,18,40,&45= 2??3??5
L.C.M of 12 ,18,40,&45= 2?2?2?3?3?5
L.C.M of 12 ,18,40,&45= 360
Now divide the largest 4 digit number 9999 by 360
9999 ? 360
9999= 360? 27 +279
Remainder= 279
Then Subtract the remainder from 9999
9999- 279= 9720
Hence, greatest number of four digits which is divisible by 12, 18, 40 & 45
= 9720

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Ayush Yesankar answered this

Find LCM of 12, 18, 40 and 45: which comes out to be 360.

Now, 360 x 30 = 10800

360 x 29 = 10800 - 360 = 10440

360 x 28 = 10080

360 x 27 = 9720

Clearly, 9720 is the largest four digit number divisible by 12, 18, 40 and 45 as 9720 will be a multiple of these numbers as it is a multiple of one of their common multiples.

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Regards

Ayush Yesankar answered this

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Neeraj Kumar Sahu answered this

We know that the Greatest number of four digits = 9999

To find the greatest number of 4 digit we have to find the L.C.M of 12, 18, 40,45

Prime factorization :
12= 2×2×3= 2²×3¹

18= 2×3×3= 2¹× 3²

40= 2×2×2×5= 2³×5

45= 3×3×5= 3²×5

L.C.M of 12 ,18,40,&45= 2³×3²×5

L.C.M of 12 ,18,40,&45= 2×2×2×3×3×5

L.C.M of 12 ,18,40,&45= 360

Now divide the largest 4 digit number 9999 by 360

9999 ÷ 360

9999= 360× 27 +279

Remainder= 279

Then Subtract the remainder from 9999

9999- 279= 9720

Hence, greatest number of four digits which is divisible by 12, 18, 40 & 45
= 9720

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LCM of 12, 18, 40, 45
And divide the LCM with greatest digit 9999 and subtract with it's reminder

Ananya Rathore answered this

(Greatest number= HCF)
So, the HCF of 12,18,40,45 is 1
Greatest four digit number is 9999
So,
9999
- 1
=9998
So,
9998 is the greatest number of four digits... which is divisible by 12,18,40,45

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