Find the greatest number which divides 51, 111, 283 equally giving the same remainder in case.

Hi!

Here is the answer to your question.

 

The given numbers are 51, 111 and 283.

111 – 51 = 60 and 283 – 111 = 172

The greatest number which divides 51, 111 and 283 leaving the same remainder is the HCF of 60 and 172.

Prime factorization of 60 = 2 × 2 × 3 × 5

Prime factorization of 172 = 2 × 2 × 43

HCF of 60 and 172 = 2 × 2 = 4

Thus, the greatest number which divides 51, 111 and 283 leaving the same remainder is 4.

 

Cheers!