# Find the initial velocity of the car which is stopped in 10 sec by applying brakes .The retardation due to brakes is 2.5m/sec sq.....

v = 0

t = 10s

a = -2.5 m/s2

v = u + at

0 = u + (-2.5)(10)

0 = u - 25

u = 25 m/s

• 39
Final vel. : 0 initial vel. : ? t : 10sec retar. : 2.5 m/s2 V=U+AT O = U+ 2.5 *10 U=25 m/s
• 4
let final velocity be o and initial velocity be u
time = 10 sec
acceleration = -2.5m/s2
according to first formula
v = u + at
where v = 0
u = ?
a = -2.5m/s2
t = 10 sec
v = u + at
0 = u + (-2.5) * 10
0 = u - 25
u = 25 m/s

• 24
Here the initial velocity is 25
• 1
Using v = u+at formula, initial velocity is 25m/s

• -2
initial velocity , u=x
final velocity,v=0
time,t=10
​retardation due to brakes,a= 2.5m/s2
​v=u+at
0=x+(-2.5)(10)
-x=-25
x=25m/s

• 0
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