find the locus of intersection of tangents to the circle x=acosQ ,Y=ASINQ at the pints whose parametric angles differ be pie/3 and pie/2 Share with your friends Share 5 Lovina Kansal answered this Dear student Let one of the points on the circle be A(acosQ,asinQ)Then the other point will be BacosQ+π3,asinQ+π3∴Equation of tangent at A=xcosQ+ysinQ=a ....(1)Equation of tangent at B=xcosQ+π3+ysinQ+π3=a ...(2)From eq(2)⇒x12cosQ-32sinQ+y12sinQ+32cosQ=a⇒12xcosQ+ysinQ-32xsinQ-ycosQ=a⇒xsinQ-ycosQ=-a3 ...(3)∴Square and add (1) and (3)xcosQ+ysinQ2+xsinQ-ycosQ2=a2+a23⇒3x2+3y2=4a2The locus of the point of intersection of the tangents 3x2+3y2-4a2=0 Regards 26 View Full Answer