find the median from the foll.data
x 5 10 15 20 25 30 35
f 1 3 17 20 10 5 4
X FREQUENCY CUMULATIVE FREQUENCY
5 1 1
10 3 4
15 17 21
20 20 41
25 10 51
30 5 56
35 4 60
HERE n=60
So, size of (N+1)/2TH item
=>size of (60+1)/2TH item ie 61/2th item
=>size of 30.5th item
Now we know that 30.5th item lies in 41 cf
Therefore, the median=20 {SINCE THE VALUE OF X CORRESPONDING TO THE (N+1)/2TH ITEM REPRESENTS THE MEDIAN VALUE}