Find the momentum of a body of mass 100grams having kinetic energy of 12 joules

Dear Student,

$$\begin{gathered} m=100 \text{g} = 0.1 \text{kg}. \\ {K}_E=\frac{1}{2}m{v}^2=12 \text{J} \\ \Rightarrow v^2=\frac{2\times 12}{m}=\frac{2\times 24}{0.1}=480 \\ \Rightarrow v=480 {\text{ms}}^{-1} \\ \text{So,momentum is} \\ P=mv=480\times 0.1=48 {\text{kgms}}^{-1} \end{gathered}$$ Regards  

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