# Find the momentum of a body of mass 100grams having kinetic energy of 12 joules

$m=100\text{g}=0.1\text{kg}.\phantom{\rule{0ex}{0ex}}{K}_{E}=\frac{1}{2}m{v}^{2}=12\text{J}\phantom{\rule{0ex}{0ex}}\Rightarrow {v}^{2}=\frac{2\times 12}{m}=\frac{2\times 24}{0.1}=480\phantom{\rule{0ex}{0ex}}\Rightarrow v=480{\text{ms}}^{-1}\phantom{\rule{0ex}{0ex}}\text{So,momentumis}\phantom{\rule{0ex}{0ex}}P=mv=480\times 0.1=48{\text{kgms}}^{-1}$

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