find the multiplicative inverse of (2+i root of 3)2 Share with your friends Share 2 Ankita Agarwal answered this Dear Student, The multiplicative inverse of a number A is another number B which when multiplied by A gives 1. Here we have the number 2+i32 . Let A = 2+i32 , we need to find B such that A×B = 1B=1A=1 2+i32 =14+i232+4i3 a-b2=a2+b2-2ab =14-1×3+4i3 i2=-1 =11+4i3×1-4i31-4i3 =1-4i312-4i32 a-ba+b=a2-b2 =1-4i31-16×i2×3 =1-4i31+48 =1-4i349 =149-4i349 Regards -1 View Full Answer
