find the multiplicative inverse of (i+1) (i+2)/ (i-1) (i-2) Share with your friends Share 0 Ankita Agarwal answered this Dear Student, The multiplicative inverse of a number A is another number B which when multiplied by A gives 1. Here we have the number i+1i+2i-1i-2 Let A =i+1i+2i-1i-2, we need to find B such that A×B = 1B=1A=1i+1i+2i-1i-2=i-1i-2i+1i+2 =i2-i-2i+2i2+i+2i+2 =-1-3i+2-1+3i+2 i2=-1 =1-3i1+3i×1-3i1-3i Multiply by its conjugate =1-3i212-3i2 a+ba-b=a2-b2 , a-b2=a2+b2-2ab =1+9i2-6i1-9i2 =1-9-6i1+9 =-8-6i10 =-4-3i5 Regards -4 View Full Answer
